document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=515616>Question 515616</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two sailboats, one averaging 20 miles per hour and the other 18 miles per hour, start at the same place and follow the same course. The slower boat arrives at the end of the course 1/6 of an hour after the faster sailboat. How far did each boat travel? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344104 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Time slower boat - time faster boat = 1/6 h<BR>\n" );
document.write( "let x be the distance\r<BR>\n" );
document.write( "\n" );
document.write( "time slower boat = x/18<BR>\n" );
document.write( "time faster boat = x/20\r<BR>\n" );
document.write( "\n" );
document.write( "x/18 - x/20 =1/6\r<BR>\n" );
document.write( "\n" );
document.write( "LCD = 180. Multiply by LCD\r<BR>\n" );
document.write( "\n" );
document.write( "10x-9x=30<BR>\n" );
document.write( "x=30\r<BR>\n" );
document.write( "\n" );
document.write( "3o miles </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );