document.write( "Question 515636: two years ago father was 3 times as old as his son and 2 year hence,twice his age will be equal to 5 times that of his son find present age ? \n" ); document.write( "
Algebra.Com's Answer #344102 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Father = f \n" ); document.write( "Present age of Son = s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Two years ago \n" ); document.write( "f-2=s-2 \n" ); document.write( "Father was 3 times as old as his son \n" ); document.write( "f-2=3(s-2) \n" ); document.write( "f-2=3s-6 \n" ); document.write( "f=3s-6+2 \n" ); document.write( "f=3s-4............(1) \n" ); document.write( "and 2 year hence, \n" ); document.write( "f+2=s+2 \n" ); document.write( "then twice his age will be equal to 5 times that of his son \n" ); document.write( "2(f+2)=5(s+2) \n" ); document.write( "2f+4=5s+10 \n" ); document.write( "2f=5s+10-4 \n" ); document.write( "2f=5s+6.............(2) \n" ); document.write( "Put the value of f in (2) from (1) \n" ); document.write( "2(3s-4)=5s+6 \n" ); document.write( "6s-8=5s+6 \n" ); document.write( "6s-5s=6+8 \n" ); document.write( "s=14 \n" ); document.write( "Put the value of s in (1) \n" ); document.write( "f=3s-4............(1) \n" ); document.write( "f=3(14)-4 \n" ); document.write( "f=42-4 \n" ); document.write( "f=38\r \n" ); document.write( "\n" ); document.write( "Present age of Father = f = 38 years old \n" ); document.write( "Present age of Son = s = 14 years old\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |