document.write( "Question 515634: Rico is twice old as Ryan.In four years,Rico's age will be three times as Ryan's age is six years ago.How old are they now? \n" ); document.write( "
Algebra.Com's Answer #344101 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of Rico = r
\n" ); document.write( "Present age of Ryan = y\r
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\n" ); document.write( "\n" ); document.write( "Rico is twice old as Ryan
\n" ); document.write( "r=2y........(1)
\n" ); document.write( "In four years,Rico's age will be three times as Ryan's age is six years ago\r
\n" ); document.write( "\n" ); document.write( "Rico age in four years = r+4
\n" ); document.write( "Ryan age six years ago = y-6\r
\n" ); document.write( "\n" ); document.write( "r+4=3(y-6)
\n" ); document.write( "r+4=3y-18
\n" ); document.write( "r=3y-18-4
\n" ); document.write( "r=3y-22.............(2)
\n" ); document.write( "Put the value of r in (2) from (1)
\n" ); document.write( "2y=3y-22
\n" ); document.write( "2y-3y=-22
\n" ); document.write( "-y=-22
\n" ); document.write( "Multiply by -1 both sides
\n" ); document.write( "y=22\r
\n" ); document.write( "\n" ); document.write( "Put the value of y in (1)
\n" ); document.write( "r=2y
\n" ); document.write( "r=2(22)
\n" ); document.write( "r=44
\n" ); document.write( "Present age of Rico = r = 44 years old
\n" ); document.write( "Present age of Ryan = y = 22 years old\r
\n" ); document.write( "\n" ); document.write( "Six years ago Ryan was = 22-6 = 16
\n" ); document.write( "In four years Rico will be = 44+4 = 48 (which is 3 times of 16)\r
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