document.write( "Question 515621: Five years ago. A's age was four times B's age, 6 years hence A's age to B's is 5:2. Find the ages of A and B at present. \n" ); document.write( "
Algebra.Com's Answer #344097 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of A = a
\n" ); document.write( "Present age of B = b\r
\n" ); document.write( "\n" ); document.write( "Five years ago
\n" ); document.write( "a-5=b-5
\n" ); document.write( "Then
\n" ); document.write( "A was 4 time of B's age
\n" ); document.write( "a-5=4(b-5)
\n" ); document.write( "a-5=4b-20
\n" ); document.write( "a=4b-20+5
\n" ); document.write( "a=4b-15..............(1)\r
\n" ); document.write( "\n" ); document.write( "In 6 years
\n" ); document.write( "A will be = a+6
\n" ); document.write( "B will be = b+6
\n" ); document.write( "Then
\n" ); document.write( "A's age to B's is 5:2
\n" ); document.write( "a+6 / b+6 = 5/2
\n" ); document.write( "2(a+6)=5(b+6)
\n" ); document.write( "2a+12=5b+30
\n" ); document.write( "2a=5b+30-12
\n" ); document.write( "2a=5b+18
\n" ); document.write( "2a=5b+18..........(2)
\n" ); document.write( "Put the value of a in (2) from (1)
\n" ); document.write( "2(4b-15)=5b+18
\n" ); document.write( "8b-30=5b+18
\n" ); document.write( "8b-5b=18+30
\n" ); document.write( "3b=48
\n" ); document.write( "3b/3=48/3
\n" ); document.write( "b=16
\n" ); document.write( "Put the value of b in (1)
\n" ); document.write( "a=4b-15
\n" ); document.write( "a=4(16)-15
\n" ); document.write( "a=64-15
\n" ); document.write( "a=49\r
\n" ); document.write( "\n" ); document.write( "Present age of A = a = 49 years old
\n" ); document.write( "Present age of B = b = 16 years old
\n" ); document.write( "Five years ago B was = 16-5 = 11
\n" ); document.write( "Five years ago A was = 49-5 = 44 (which is 4 times of 11)
\n" ); document.write( "In six years there ages will be in ratio = 49+6 / 16+6 = 55/22=5/2
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