document.write( "Question 515621: Five years ago. A's age was four times B's age, 6 years hence A's age to B's is 5:2. Find the ages of A and B at present. \n" ); document.write( "
Algebra.Com's Answer #344097 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of A = a \n" ); document.write( "Present age of B = b\r \n" ); document.write( "\n" ); document.write( "Five years ago \n" ); document.write( "a-5=b-5 \n" ); document.write( "Then \n" ); document.write( "A was 4 time of B's age \n" ); document.write( "a-5=4(b-5) \n" ); document.write( "a-5=4b-20 \n" ); document.write( "a=4b-20+5 \n" ); document.write( "a=4b-15..............(1)\r \n" ); document.write( "\n" ); document.write( "In 6 years \n" ); document.write( "A will be = a+6 \n" ); document.write( "B will be = b+6 \n" ); document.write( "Then \n" ); document.write( "A's age to B's is 5:2 \n" ); document.write( "a+6 / b+6 = 5/2 \n" ); document.write( "2(a+6)=5(b+6) \n" ); document.write( "2a+12=5b+30 \n" ); document.write( "2a=5b+30-12 \n" ); document.write( "2a=5b+18 \n" ); document.write( "2a=5b+18..........(2) \n" ); document.write( "Put the value of a in (2) from (1) \n" ); document.write( "2(4b-15)=5b+18 \n" ); document.write( "8b-30=5b+18 \n" ); document.write( "8b-5b=18+30 \n" ); document.write( "3b=48 \n" ); document.write( "3b/3=48/3 \n" ); document.write( "b=16 \n" ); document.write( "Put the value of b in (1) \n" ); document.write( "a=4b-15 \n" ); document.write( "a=4(16)-15 \n" ); document.write( "a=64-15 \n" ); document.write( "a=49\r \n" ); document.write( "\n" ); document.write( "Present age of A = a = 49 years old \n" ); document.write( "Present age of B = b = 16 years old \n" ); document.write( "Five years ago B was = 16-5 = 11 \n" ); document.write( "Five years ago A was = 49-5 = 44 (which is 4 times of 11) \n" ); document.write( "In six years there ages will be in ratio = 49+6 / 16+6 = 55/22=5/2 \n" ); document.write( " |