document.write( "Question 513603: The Sum of the ages of A and B is 42 years.\r
\n" ); document.write( "\n" ); document.write( "3 years back, the age of A was 5 times the age of B. Find the difference between the present ages of A and B.\r
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Algebra.Com's Answer #344094 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of A = a
\n" ); document.write( "Present age of B = b\r
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\n" ); document.write( "\n" ); document.write( "The Sum of the ages of A and B is 42 years.
\n" ); document.write( "a+b=42
\n" ); document.write( "a=42-b..........(1)
\n" ); document.write( "3 years back
\n" ); document.write( "a-3=b-3
\n" ); document.write( "then
\n" ); document.write( "the age of A was 5 times the age of B
\n" ); document.write( "a-3=5(b-3)
\n" ); document.write( "a-3=5b-15
\n" ); document.write( "a=5b-15+3
\n" ); document.write( "a=5b-12.............(2)
\n" ); document.write( "Subtitue the value of a in (2) from (1)
\n" ); document.write( "42-b=5b-12
\n" ); document.write( "-b-5b=-12-42
\n" ); document.write( "-6b=-54
\n" ); document.write( "-6b/-6=-54/-6
\n" ); document.write( "b=9
\n" ); document.write( "Put the value of b in (1)
\n" ); document.write( "a=42-9
\n" ); document.write( "a=33
\n" ); document.write( "Present age of A = a = 33 years old
\n" ); document.write( "Present age of B = b = 9 years old\r
\n" ); document.write( "\n" ); document.write( "Three years bakc B was = 9-3 = 6
\n" ); document.write( "Three years bakc A was = 33-3 = 30 (which is 5 times of 6) \r
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