document.write( "Question 513603: The Sum of the ages of A and B is 42 years.\r
\n" );
document.write( "\n" );
document.write( "3 years back, the age of A was 5 times the age of B. Find the difference between the present ages of A and B.\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #344094 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of A = a \n" ); document.write( "Present age of B = b\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The Sum of the ages of A and B is 42 years. \n" ); document.write( "a+b=42 \n" ); document.write( "a=42-b..........(1) \n" ); document.write( "3 years back \n" ); document.write( "a-3=b-3 \n" ); document.write( "then \n" ); document.write( "the age of A was 5 times the age of B \n" ); document.write( "a-3=5(b-3) \n" ); document.write( "a-3=5b-15 \n" ); document.write( "a=5b-15+3 \n" ); document.write( "a=5b-12.............(2) \n" ); document.write( "Subtitue the value of a in (2) from (1) \n" ); document.write( "42-b=5b-12 \n" ); document.write( "-b-5b=-12-42 \n" ); document.write( "-6b=-54 \n" ); document.write( "-6b/-6=-54/-6 \n" ); document.write( "b=9 \n" ); document.write( "Put the value of b in (1) \n" ); document.write( "a=42-9 \n" ); document.write( "a=33 \n" ); document.write( "Present age of A = a = 33 years old \n" ); document.write( "Present age of B = b = 9 years old\r \n" ); document.write( "\n" ); document.write( "Three years bakc B was = 9-3 = 6 \n" ); document.write( "Three years bakc A was = 33-3 = 30 (which is 5 times of 6) \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |