document.write( "Question 515595: A doll was sold for $45 at a loss of 10%. What was the original price?\r
\n" ); document.write( "\n" ); document.write( "Original Price has to be greater than 45 since it was sold at a loss, so:
\n" ); document.write( "Loss was only 10%, so there was a 'gain' of 90%, for want of a better term.\r
\n" ); document.write( "\n" ); document.write( "So 90% of some number gives a loss of 45.
\n" ); document.write( "0.9(some number) = 45
\n" ); document.write( "some number = \"45%2F0.9\"
\n" ); document.write( "some number = 50\r
\n" ); document.write( "\n" ); document.write( "I'm not really comfortable with this method. Could I be, kindly, shown alternatives?
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Algebra.Com's Answer #344084 by drcole(72)\"\" \"About 
You can put this solution on YOUR website!
You have a good method. Here's another way to get to the same equation. Let x be the original price. 10% of the original price is 0.10x. If the doll was sold at a loss of 10%, then the price it was sold at would be:\r
\n" ); document.write( "\n" ); document.write( "x - 0.10x\r
\n" ); document.write( "\n" ); document.write( "We know that the doll was sold at $45, so this gives the algebraic equation:\r
\n" ); document.write( "\n" ); document.write( "x - 0.10x = 45
\n" ); document.write( "0.9x = 45 (combining like terms)\r
\n" ); document.write( "\n" ); document.write( "Now we're back to the equation you figured out in a slightly different way.
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