document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51615>Question 51615</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the slope of the line that passes through points (-4,5) and (2,3). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34408 by </B><A HREF=/tutors/aboutme.mpl?userid=rchill><B>rchill(405)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rchill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Slope m is defined as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=%28y2-y1%29%2F%28x2-x1%29 ALIGN=MIDDLE  ALT=\"m=%28y2-y1%29%2F%28x2-x1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Use your points in any order as long as you're consistent -- let's make (-4,5) be (x1,y1).  With substitution we get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=%283-5%29%2F%282-%28-4%29%29 ALIGN=MIDDLE  ALT=\"m=%283-5%29%2F%282-%28-4%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, which simplifies to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=-2%2F6 ALIGN=MIDDLE  ALT=\"m=-2%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" > and that reduces to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=-1%2F3 ALIGN=MIDDLE  ALT=\"m=-1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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