document.write( "Question 51610: solve the quadratic equation:
\n" ); document.write( "\"%28x%2B3%29%5E2=81\"\r
\n" ); document.write( "\n" ); document.write( "thanks a lot
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Algebra.Com's Answer #34406 by rchill(405)\"\" \"About 
You can put this solution on YOUR website!
Doing it the easy way: Let's take the square root of both sides: \"sqrt%28%28x%2B3%29%5E2%29=sqrt%2881%29\", which simplifies to \"x%2B3=9\". Because we are squaring the (x+3) though, that means that we could have two solutions, one positive and one negative (\"x%2B3=-9\". Solving for the first equation, subtract 3 from both sides: \"x%2B3-3=9-3\", which simplifies to \"x=6\". Now solve for the second equation: \"x%2B3-3=-9-3\", which simplifies to \"x=-12\". So there are two solutions for x: 6 and -12. An alternative way of solving is by using the quadratic equation and discriminant. \n" ); document.write( "
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