document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=515538>Question 515538</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist wants to make 44 mL of a 16% acid solution by mixing a 10% acid solution and an 18% acid solution. How many milliliters of each solution should the chemist use?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344055 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344055\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist wants to make 44 mL of a 16% acid solution by mixing a 10% acid solution and an 18% acid solution. How many milliliters of each solution should the chemist use? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.10x + 0.18(44-x) = 0.16*44<BR>\n" );
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document.write( "10x + 18*44 - 18x = 16*44<BR>\n" );
document.write( "-8x = -2*44<BR>\n" );
document.write( "x = 11 mL (amt. of 10% solution needed)<BR>\n" );
document.write( "44-x = 33 mL (amt. of 18% solution needed)<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "===================== </SPAN>\n" );
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