document.write( "Question 515532: For what value of 2x^2-3x+c=0 have one and only one real root? \n" ); document.write( "
Algebra.Com's Answer #344043 by MathLover1(20850)\"\" \"About 
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So, for what value of c will \"2x%5E2+-+3x+%2B+c+=+0\" have one and only one real root? To answer this question, let's think about the quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b%2B-+sqrt%28b%5E2+-+4ac%29%29+%2F+2a\"\r
\n" ); document.write( "\n" ); document.write( "Specifically take note of the \"sqrt%28b%5E2+-+4ac%29\". What's inside of this radical is known as the determinant, because it determines how many roots there will be.\r
\n" ); document.write( "\n" ); document.write( "\"If\" this \"determinant\" is \"negative\", then there are \"no\"\"+real\" solutions. This is because you can't take the square root of a negative number without using imaginary numbers. Therefore, a negative determinant implies no real roots.\r
\n" ); document.write( "\n" ); document.write( "\"If\" this \"determinant\" is \"positive\", then there are \"2\"\"+real\" solutions. This is because of the ± in the quadratic formula. \r
\n" ); document.write( "\n" ); document.write( "\"If\" the \"determinant\" happened to be \"1\", then you'd have \"two\"\"+answers\": one you would have to add the \"1\", and the other you would have to subtract the \"1\".\r
\n" ); document.write( "\n" ); document.write( "\"If\" the \"determinant\" is \"zero\", then there is \"only\"\"+1\"\"+real\" solution. This is because + or - zero leaves the quadratic formula unchanged. In summary:\r
\n" ); document.write( "\n" ); document.write( "One real solution: \"b%5E2+-+4ac=0\"
\n" ); document.write( "Two real solutions:\"+b%5E2+-+4ac%3E0\"
\n" ); document.write( "No real solutions: \"b%5E2+-+4ac%3C0\"\r
\n" ); document.write( "\n" ); document.write( "So let's solve to see when the determinant equals zero, so there will be only one real root. We will use the a, b, and c values from the equation you provided earlier.\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2+-3x+%2B+c+=+0\"
\n" ); document.write( "\"a+=+2\"
\n" ); document.write( "\"b+=+-3\"
\n" ); document.write( "\"c+=+Unknown\"\r
\n" ); document.write( "\n" ); document.write( "Let's set the determinant equal to zero, and then substitute the known values:\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2+-+4ac+=+0\"
\n" ); document.write( "\"%28-3%29%5E2+-+4%282%29%28c%29+=+0\"
\n" ); document.write( "\"%28-3%29%5E2+-+8c+=+0\"
\n" ); document.write( "\"9+-+8c+=+0\"
\n" ); document.write( "\"9+=+8c\"
\n" ); document.write( "\"9%2F8+=+c\"\r
\n" ); document.write( "\n" ); document.write( "\"c\" must be equal to \"9%2F8\" for the equation to have one and only one real root.\r
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