document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=515491>Question 515491</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An automobile radiator contains 16L of antifreeze and water. This mixture is 30% antifreeze. How much of this mixture should be drained and replaced with pure antifreeze so that the mixture will be 50% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344037 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An automobile radiator contains 16L of antifreeze and water. This mixture is 30% antifreeze. How much of this mixture should be drained and replaced with pure antifreeze so that the mixture will be 50% antifreeze?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "alcohol - alcohol + alcohol = alcohol<BR>\n" );
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document.write( "0.30*16 - 0.30x + 1.00x = 0.50*16<BR>\n" );
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document.write( "30*16 - 30x + 100x = 50*16<BR>\n" );
document.write( "70x = 20*16<BR>\n" );
document.write( "x = (2/7)16 = 4.57 L (amt. to be removed and replaced)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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