document.write( "Question 515488: A boat can go 20 km downstream in 2 hours. The return trip takes 5 hours. What would the speed of the boat be if there was no current? What is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #344003 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! d = r*t is the basic distance equation. \n" ); document.write( ". \n" ); document.write( "d = 20km \n" ); document.write( ". \n" ); document.write( "s = speed of the boat in calm water \n" ); document.write( "c = speed of the current \n" ); document.write( "so \n" ); document.write( "r = s-c going upstream (against the current) \n" ); document.write( "r = s+c going down stream (with the current) \n" ); document.write( ". \n" ); document.write( "Going downstream... \n" ); document.write( "d/r = 2 hr \n" ); document.write( "d/(s+c) = 2 \n" ); document.write( "20 = 2(s+c) \n" ); document.write( "2(s+c) = 20 \n" ); document.write( "s+c = 10 \n" ); document.write( ". \n" ); document.write( "Going upstream \n" ); document.write( "d/r = 5 hr \n" ); document.write( "d/(s-c) = 5 \n" ); document.write( "20 = 5(s-c) \n" ); document.write( "5(s-c) = 20 \n" ); document.write( "s-c = 4 \n" ); document.write( ". \n" ); document.write( "s + c = 10 \n" ); document.write( "s - c = 4 \n" ); document.write( "---------- \n" ); document.write( "2s = 14 \n" ); document.write( "s = 7 km/h \n" ); document.write( ". \n" ); document.write( "c = 10-s \n" ); document.write( "c = 3 km/h \n" ); document.write( ". \n" ); document.write( "Check the distances \n" ); document.write( ". \n" ); document.write( "2 * (7+3) = 20 km \n" ); document.write( "5 * (7-3) = 20 km \n" ); document.write( ". \n" ); document.write( "Answer: The boat can achieve 7 km/h in still water; the current is 3 km/h. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |