document.write( "Question 515463: A passenger train's speed is 60mi/h,and a freight train's is 40mi/h. The passenger train travels the same distance in 1.5h less time than the freight train. How long does each train take to make the trip? \n" ); document.write( "
Algebra.Com's Answer #344001 by ankor@dixie-net.com(22740)\"\" \"About 
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A passenger train's speed is 60mi/h, and a freight train's is 40mi/h.
\n" ); document.write( " The passenger train travels the same distance in 1.5h less time than the freight train.
\n" ); document.write( " How long does each train take to make the trip?
\n" ); document.write( ":
\n" ); document.write( "let t = pass train travel time
\n" ); document.write( "then
\n" ); document.write( "(t+1.5) = freight's time
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation: dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Pass dist = freight dist
\n" ); document.write( "60t = 40(t+1.5)
\n" ); document.write( "60t = 40t + 60
\n" ); document.write( "69t - 40t = 60
\n" ); document.write( "20t = 60
\n" ); document.write( "t = 60/20
\n" ); document.write( "t = 3 hrs for pass train to make the trip
\n" ); document.write( "then
\n" ); document.write( "3 + 1.5 = 4.5 hrs for freight to do it
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check the solution, by finding the dist each traveled, should be equal
\n" ); document.write( "3(60) = 180 mi
\n" ); document.write( "4.5(40)= 180 mi \n" ); document.write( "
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