document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51569>Question 51569</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please show me how to work these problems using the substitution method:<BR>\n" );
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document.write( "1/2x+1/3y=3<BR>\n" );
document.write( "y=3x      	 	  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34400 by </B><A HREF=/tutors/aboutme.mpl?userid=math_kid><B>math_kid(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_kid><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> All you have 2 do is plug in 3x for y and then your problem should read 1/2x+ 1/3(3x)=3! So now all you have to do is simplify 1/3 and 3x. You should get x because the 1/3 and the 3 should cancel out. Now your problem should read: 1/2x+ x=3 and then you finish the problem and you should get 3/2x=3 so u multiply 2 on both sides then u divide by 3 on both sides and you should then get x=2 as your final answer.  </SPAN>\n" );
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