document.write( "Question 515468: solve 4 sin^2 x =2 for 0 <= x <= 180 \n" ); document.write( "
Algebra.Com's Answer #343995 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! solve 4 sin^2 x =2 for 0 <= x <= 180 \n" ); document.write( "** \n" ); document.write( "4 sin^2 x =2 \n" ); document.write( "sin^2x=2/4=1/2 \n" ); document.write( "sin x=√(1/2)=1/√2 \n" ); document.write( "x=45º and 135º (in quadrants I and II where sin >0) \n" ); document.write( " |