document.write( "Question 515372: Please help me to solve this equation y=x+2.
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Algebra.Com's Answer #343990 by oberobic(2304) $\"\"$ $\"About$

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y = x+2 is a linear equation.
\n" ); document.write( "when x=0, y =2, so that is the y-intercept (0,2)
\n" ); document.write( "when x=-2, y=0, so that is the x-intercept (-2,0)
\n" ); document.write( "with two points you can draw a line.
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\n" ); document.write( "y =x^2 is a quadratic equation, specifically a paraola
\n" ); document.write( "x = 0 results in y=0, so the parabola intersects the origin.
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\n" ); document.write( "The graph will help you find the points that solve both equations simultaneously.
\n" ); document.write( " $\"+graph%28500%2C500%2C-5%2C5%2C-5%2C5%2Cx%2B2%2Cx%2Ax%29+\"$
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\n" ); document.write( "We also can set the equations equal to one another to find the simultaneous solutions.
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\n" ); document.write( "x^2 = x+2
\n" ); document.write( "x^2 -x -2 = 0
\n" ); document.write( "(x-2)(x+1) = 0
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\n" ); document.write( "So the roots (or zeroes) are x=2 and x=-1.
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\n" ); document.write( "When x=2, y=4: (2,4)
\n" ); document.write( "when x=-1, y=1: (-1,1) \n" ); document.write( "

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