document.write( "Question 515269: Hello my name is Suzy. I need help on a algebra word problem. I have worked it out a few times and never got the right answer. Here is the problem.\r
\n" ); document.write( "\n" ); document.write( "A long distance truck driver traveled 160 miles in one direction during a snow storm. The return trip in rainy weather was accomplished at double the speed and took 4 hours less time. Find the speed going.\r
\n" ); document.write( "\n" ); document.write( "I know that I want to use the equation t=d
\n" ); document.write( " r
\n" ); document.write( "But from there I am lost.
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Algebra.Com's Answer #343970 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A long distance truck driver traveled 160 miles in one direction during a snow storm.
\n" ); document.write( " The return trip in rainy weather was accomplished at double the speed and took 4 hours less time.
\n" ); document.write( "Find the speed going.
\n" ); document.write( ":
\n" ); document.write( "First find the time.
\n" ); document.write( "let t = travel time required in snow
\n" ); document.write( "then
\n" ); document.write( "(t-4) = time required in rain
\n" ); document.write( ":
\n" ); document.write( "Write a speed equation: s = dist/time
\n" ); document.write( ":
\n" ); document.write( "Rain speed = twice snow speed
\n" ); document.write( "\"160%2F%28%28t-4%29%29\" = \"2%28160%2Ft%29\"
\n" ); document.write( "\"160%2F%28%28t-4%29%29\" = \"320%2Ft\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "320(t-4) = 160t
\n" ); document.write( "320t - 1280 = 160t
\n" ); document.write( "320t - 160t = 1280
\n" ); document.write( "160t = 1280
\n" ); document.write( "t = \"1280%2F160\"
\n" ); document.write( "t = 8 hrs required thru the snow, then 4 hrs thru the rain
\n" ); document.write( ":
\n" ); document.write( "Find the speeds
\n" ); document.write( "160/8 = 20 mph thru snow
\n" ); document.write( "160/4 = 40 mph thru rain
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