document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=515421>Question 515421</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the length and width of a rectangle are doubled, how do the perimeters of the original and new rectangles compare? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343962 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = perimeter = 2(L+W) = 2L + 2W<BR>\n" );
document.write( "A = area = L*W<BR>\n" );
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document.write( "If you double L and W, you have 2L and 2W<BR>\n" );
document.write( "so<BR>\n" );
document.write( "P = 2(2L + 2W) = 4L + 4W<BR>\n" );
document.write( "which means the perimeter has doubled from 2L + 2W to 4L + 4W.<BR>\n" );
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document.write( "A = 2L*2W<BR>\n" );
document.write( "A = 4L*W<BR>\n" );
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document.write( "However, the area has quadrupled.<BR>\n" );
document.write( "Why?<BR>\n" );
document.write( "2*2 = 4<BR>\n" );
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document.write( "As a check, consider a rectangle with sides = 4 ft.<BR>\n" );
document.write( "(Yes, it's a square.)<BR>\n" );
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document.write( "P = 2(4+4) = 2(8) = 16 ft<BR>\n" );
document.write( "A = 4*4 = 16 sq ft<BR>\n" );
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document.write( "Now double the sides = 8 ft<BR>\n" );
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document.write( "P = 2(8+8) = 2*16 = 32<BR>\n" );
document.write( "A = 8*8 = 64<BR>\n" );
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document.write( "The perimeter doubled from 16 to 32 ft.<BR>\n" );
document.write( "The area quadrupled from 16 to 64.<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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