document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51441>Question 51441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of Raisind @ $2.20/lb must be mixed with 15 lbs of nuts @ $4.00/lb to restult in a trail mix worth $ 3.00/lb? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34396 by </B><A HREF=/tutors/aboutme.mpl?userid=music974><B>music974(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=music974><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok well first we must make a table like this... \r<BR>\n" );
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document.write( "	     Amt.      $     Total   <BR>\n" );
document.write( "Raisins	  r	  2.20	    2.20r<BR>\n" );
document.write( "Nuts	  15	  4.00	    60<BR>\n" );
document.write( "Total	 15+r	  3.00	    (15+r)3\r<BR>\n" );
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document.write( "Now we have to write an equation which would be 2.2r+60=(15+r)3 then we would distribute the three to get 2.2r+60=45+3r Then subtract both sides by 45 to get 2.2r+15=3r. Now subtract each side by 2.2r to get 15=.8r. Now multiply each side by 10 to get rid of the decimal thus getting 150=8r. Then divide both sides by 8 to get r=18.5. So you would need 18.5 pounds of raisins. Hope this helps!!  </SPAN>\n" );
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