document.write( "Question 515292: 1 year ago,a man was 8 times as old as his son.now his age is equal to the square of his son's age.find their ages \n" ); document.write( "
Algebra.Com's Answer #343921 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of man = m
\n" ); document.write( "Present age of son = s\r
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\n" ); document.write( "\n" ); document.write( "now his age is equal to the square of his son's age
\n" ); document.write( "m=s^2...........(1)
\n" ); document.write( "1 year ago
\n" ); document.write( "m-1=s-1
\n" ); document.write( "Then
\n" ); document.write( "man was 8 times as old as his son
\n" ); document.write( "m-1=8(s-1)
\n" ); document.write( "m-1=8s-8
\n" ); document.write( "m=8s-8+1
\n" ); document.write( "m=8s-7\r
\n" ); document.write( "\n" ); document.write( "Put the value of m from (1) to above equation
\n" ); document.write( "s^2=8s-7
\n" ); document.write( "s^2-8s+7=0
\n" ); document.write( "s^2-7s-s+7=0
\n" ); document.write( "s(s-7)-1(s-7)=0
\n" ); document.write( "(s-7)(s-1)=0
\n" ); document.write( "s-7=0 or s-1=o
\n" ); document.write( "s=7 or s=1\r
\n" ); document.write( "\n" ); document.write( "Present age of son is 7 years old or 1 year old, but we have been told that the man age one years ago was 8 times the son's age. If we assume that son is 1 year old it means one years back he is age was 0 and the square of the 0 will remain 0, so present age of son cannot be 1 year, Son is 7 years old.\r
\n" ); document.write( "\n" ); document.write( "S=7
\n" ); document.write( "Put the value of s in equaton (1)
\n" ); document.write( "m=s^2
\n" ); document.write( "m=7^2
\n" ); document.write( "m=49\r
\n" ); document.write( "\n" ); document.write( "Present age of man = m = 49 years old
\n" ); document.write( "Present age of son = s = 7 years old\r
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