document.write( "Question 515337: find the vertex, the line of symetry, the minumum/maximum value of the quadratic function and graph. -(x+5)^2-6
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document.write( "is it min or max=
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document.write( "Thank you! \n" );
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Algebra.Com's Answer #343914 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! -(x+5)^2 -6 = -(x+5)(x+5) -6 = -(x^2 +10x + 25) -6 \n" ); document.write( ". \n" ); document.write( "-(x^2 +10x + 25) -6 = -x^2 -10x -25 -6 = -x^2 -10x -31 \n" ); document.write( ". \n" ); document.write( "The graph will help orient us to the solution \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The vertex has a x value of -b/2a = -(-10)/(-2*1) = -5 \n" ); document.write( "When x=-5 \n" ); document.write( "y = -x^2 -10x -31 \n" ); document.write( "y = -25 +50 -31 \n" ); document.write( "y = -6 \n" ); document.write( ". \n" ); document.write( "The vertex = (-5,-6). \n" ); document.write( ". \n" ); document.write( "The line of symmetry is x=-5, a vertical line. \n" ); document.write( ". \n" ); document.write( "Since the parabola opens 'down' we know the vertex is the maximum. \n" ); document.write( ". \n" ); document.write( "We also know this from the graph. \n" ); document.write( ". \n" ); document.write( "And we can apply calculus to set the first derivative = 0. \n" ); document.write( "dy/dx = -2x -10 = 0 \n" ); document.write( "2x = -10 \n" ); document.write( "x = -5 \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |