document.write( "Question 515261: find two consecutive whole numbers such that the sum of their square is 41. \n" ); document.write( "

Algebra.Com's Answer #343877 by Maths68(1474) $\"\"$ $\"About$

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Let
\n" ); document.write( "One number = x
\n" ); document.write( "Other number = x+1\r
\n" ); document.write( "\n" ); document.write( "sum of their square = 41\r
\n" ); document.write( "\n" ); document.write( "x^2+(x+1)^=41
\n" ); document.write( "x^2+x^2+2x+1=41
\n" ); document.write( "2x^2+2x+1-41=0
\n" ); document.write( "2x^2+2x-40=0
\n" ); document.write( "2*(x^2+x-20)=0
\n" ); document.write( "2*(x^2+x-20)/2=0/2
\n" ); document.write( "x^2+x-20=0
\n" ); document.write( "x^2-4x+5x-20=0
\n" ); document.write( "x(x-4)+5(x-4)=0
\n" ); document.write( "(x-4)(x+5)=0
\n" ); document.write( "x-4=0 or x+5=o
\n" ); document.write( "x=4 or x=-5\r
\n" ); document.write( "\n" ); document.write( "One number = x = 4
\n" ); document.write( "Other number = x+1 = 4+1 = 5\r
\n" ); document.write( "\n" ); document.write( "4^2+5^2=41
\n" ); document.write( "16+25=41
\n" ); document.write( "41=41\r
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