document.write( "Question 515157: what is standard form of the equation of the line passing through the point (-4,-2) and perpendicular to the line y=-2/7x+1 \n" ); document.write( "

Algebra.Com's Answer #343823 by mananth(16946) $\"\"$ $\"About$

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1 y = -2/7 x + 1
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = -2/7 x + 1
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = -2/7
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be 7/2
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\n" ); document.write( "m= 7/2 ,point ( -4 , -2 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "-2 = -14.00 + b
\n" ); document.write( "b= 12
\n" ); document.write( "m= 7/2
\n" ); document.write( "The required equation is y =7/2 x + 12
\n" ); document.write( "m.ananth@hotmail.ca
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