document.write( "Question 515181: A boat can travel 114 miles downstream in the same time that it can travel 24 miles upstream. If the boat can travel 23 miles per hour in still water,find the speed of the current. \n" ); document.write( "

Algebra.Com's Answer #343786 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"c\"$ = speed of current
\n" ); document.write( "Let $\"s\"$ = speed of boat in still water
\n" ); document.write( "given:
\n" ); document.write( "Going downstream:
\n" ); document.write( "(1) $\"+114+=+%28+s+%2B+c+%29%2At+\"$
\n" ); document.write( "Going upstream:
\n" ); document.write( "(2) $\"+24+=+%28+s+-+c+%29%2At+\"$
\n" ); document.write( "-------------------
\n" ); document.write( "(1) $\"+114+=+%28+23+%2B+c+%29%2At+\"$
\n" ); document.write( "(2) $\"+24+=+%28+23+-+c+%29%2At+\"$
\n" ); document.write( "-------------------
\n" ); document.write( "(1) $\"+114+=+23t+%2B+c%2At+\"$
\n" ); document.write( "(2) $\"+24+=+23t+-+c%2At+\"$
\n" ); document.write( "Add the equations
\n" ); document.write( " $\"+138+=+46t+\"$
\n" ); document.write( " $\"+t+=+3+\"$
\n" ); document.write( "and, since
\n" ); document.write( "(1) $\"+114+=+23t+%2B+c%2At+\"$
\n" ); document.write( "(1) $\"+114+=+23%2A3+%2B+3c+\"$
\n" ); document.write( "(1) $\"+3c+=+114+-+69+\"$
\n" ); document.write( "(1) $\"+3c+=+45+\"$
\n" ); document.write( "(1) $\"+c+=+15+\"$
\n" ); document.write( "The speed of the current is 15 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+24+=+%28+s+-+c+%29%2At+\"$
\n" ); document.write( "(2) $\"+24+=+%28+23+-+15+%29%2A3+\"$
\n" ); document.write( "(2) $\"+24+=+8%2A3+\"$
\n" ); document.write( "(2) $\"+24+=+24+\"$
\n" ); document.write( "OK \n" ); document.write( "

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