document.write( "Question 514833: A trip involves 15 miles on a dirt trail and 90 miles on a freeway. The velocity for the freeway portion was 30 mph more than the velocity for the dirt trail portion. The entire trip took 2 hours. What was the velocity, in miles per hour, for each part of the trip? \n" ); document.write( "
Algebra.Com's Answer #343784 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A trip involves 15 miles on a dirt trail and 90 miles on a freeway. \n" ); document.write( " The velocity for the freeway portion was 30 mph more than the velocity for the dirt trail portion. \n" ); document.write( " The entire trip took 2 hours. \n" ); document.write( "What was the velocity, in miles per hour, for each part of the trip? \n" ); document.write( ": \n" ); document.write( "Let s = speed on dirt \n" ); document.write( "then \n" ); document.write( "(s+30) = speed on freeway \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "dirt time + freeway time = 2 hrs \n" ); document.write( " \n" ); document.write( "multiply by s(s+30), results: \n" ); document.write( "15(s+30) + 90s = 2s(s+30) \n" ); document.write( "15s + 450 + 90s = 2s^2 + 60s \n" ); document.write( "105s + 450 = 2s^2 + 60s \n" ); document.write( "0 = 2s^2 + 60s - 105s - 450 \n" ); document.write( "A quadratic equation \n" ); document.write( "2s^2 - 45s - 450 = 0 \n" ); document.write( "Factors to: \n" ); document.write( "(2s + 15)(s - 30) = 0 \n" ); document.write( "The positive solution \n" ); document.write( "s = 30 mph on dirt \n" ); document.write( "then \n" ); document.write( "30+30 = 60 mph on the freeway \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can check this by finding the actual time at each speed \n" ); document.write( " |