document.write( "Question 514968: What is the center of this hyperbola: -x^2+4y^2-6x-48y+139=0 \n" ); document.write( "

Algebra.Com's Answer #343762 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
What is the center of this hyperbola: -x^2+4y^2-6x-48y+139=0
\n" ); document.write( "**
\n" ); document.write( "-x^2+4y^2-6x-48y+139=0
\n" ); document.write( "multiply by (-1)
\n" ); document.write( "x^2-4y^2+6x+48y-139=0
\n" ); document.write( "complete the square
\n" ); document.write( "(x^2+6x+9)-4(y^2-12y+36)=139+9-144=4
\n" ); document.write( "(x+3)^2-4(y-6)^2=4
\n" ); document.write( "(x+3)^2/4-(y-6)^2/1=1
\n" ); document.write( "This is an equation of a hyperbola with horizontal major axis of the standard form:
\n" ); document.write( "(x+h)^2/a^2-(y-k)^2/b^2=1, with (h,k) being the center of the hyperbola.
\n" ); document.write( "For given equation:
\n" ); document.write( "Center is at (-3,6) \n" ); document.write( "

\n" );