document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=515015>Question 515015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you foil in reverse?  When two numbers multipled together equal the last number of the equation and then the same two numbers must add up to te number in the middle of the equation. Is there a trick to solving these?  Example:29y+41+50 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343677 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think there is a method where complex numbers are used.<BR>\n" );
document.write( "There is a book by The physicist George Gamow called<BR>\n" );
document.write( " 1-2-3 infinity in which he uses complex numbers to <BR>\n" );
document.write( "find a buried treasure. I'm not sure if that can be directly<BR>\n" );
document.write( "applied or not. </SPAN>\n" );
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