document.write( "Question 515025: Jesse rents a moving van for $75 and must pay $2 per mile. The following week, Alex rents the same van, is charged $80 for the rental and $1.50 per mile. If they each paid the same amount and drove the same number of miles, how far did they each travel? \n" ); document.write( "

Algebra.Com's Answer #343673 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"m\"$ = the distance in miles each traveled
\n" ); document.write( "Let $\"+C+\"$ = cost for each
\n" ); document.write( "Jesse's equation:
\n" ); document.write( " $\"+C+=+75+%2B+2m+\"$
\n" ); document.write( "Alex's equation:
\n" ); document.write( " $\"+C+=+80+%2B+1.5m+\"$
\n" ); document.write( "Since the each had the same cost,
\n" ); document.write( " $\"+75+%2B+2m+=+80+%2B+1.5m+\"$
\n" ); document.write( " $\"+.5m+=+80+-+75+\"$
\n" ); document.write( " $\"+.5m+=+5+\"$
\n" ); document.write( " $\"+m+=+10+\"$
\n" ); document.write( "Each traveled 10 miles
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+C+=+75+%2B+2%2A10+\"$
\n" ); document.write( " $\"+C+=+95+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+C+=+80+%2B+1.5%2A10+\"$
\n" ); document.write( " $\"+C+=+80+%2B+15+\"$
\n" ); document.write( " $\"+C+=+95+\"$
\n" ); document.write( "OK \n" ); document.write( "

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