document.write( "Question 514934: The 17th term of an arithmetic progression is 81 and the 33th term is 145. Find a and d\r
\n" ); document.write( "\n" ); document.write( "a=first term
\n" ); document.write( "d=common difference
\n" ); document.write( "

Algebra.Com's Answer #343641 by plover(15)\"\" \"About 
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From the data
\n" ); document.write( "let the seventeenth number be x and the 33rd number in the AP be y
\n" ); document.write( "x=a+(n-1)d
\n" ); document.write( "x=a+(17-1)d (since it is given n=17)
\n" ); document.write( "x=a+16d
\n" ); document.write( "81=a+16d (1) (given 17th term is 81)
\n" ); document.write( "Also
\n" ); document.write( "y=a+(33-1)d
\n" ); document.write( "y=a+32d
\n" ); document.write( "145=a +32d (2) (given 33rd term is 145)\r
\n" ); document.write( "\n" ); document.write( "(1)-(2)\r
\n" ); document.write( "\n" ); document.write( "81-145=-16d
\n" ); document.write( "-64=-16d
\n" ); document.write( "d=4
\n" ); document.write( "From 1
\n" ); document.write( "81=a+16d
\n" ); document.write( "a=81-16*4
\n" ); document.write( " =81-64
\n" ); document.write( " =17
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