document.write( "Question 514928: three years ago father was 7 times as old as his son three year hence the fathers age would be 4 times that of his son what is the present age of his father \n" ); document.write( "
Algebra.Com's Answer #343628 by lwsshak3(11628)\"\" \"About 
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three years ago father was 7 times as old as his son three year hence the fathers age would be 4 times that of his son what is the present age of his father
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\n" ); document.write( "let x=father's present age
\n" ); document.write( "let y=son's age 3 yrs ago
\n" ); document.write( "..
\n" ); document.write( "3 years ago:
\n" ); document.write( "father's age=(x-3)
\n" ); document.write( "(x-3)/y=7
\n" ); document.write( "..
\n" ); document.write( "3 years hence:
\n" ); document.write( "father's age=(x+3)
\n" ); document.write( "son's age=(y+6)
\n" ); document.write( "(x+3)/(y+6)=4
\n" ); document.write( "..
\n" ); document.write( "Equations:
\n" ); document.write( "x-3=7y
\n" ); document.write( "x+3=4(y+6)=4y+24
\n" ); document.write( "x-21=4y
\n" ); document.write( "18=3y
\n" ); document.write( "y=6
\n" ); document.write( "x=7y+3=42+3=45
\n" ); document.write( "ans:
\n" ); document.write( "present age of father=45
\n" ); document.write( "
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