document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513562>Question 513562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.) sin < 0, tan < 0, what quadrant will both be in?\r<BR>\n" );
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document.write( "2.) Find the exact value of tan theta, given that sin theta = -1/6 and theta is in quadrant IV.\r<BR>\n" );
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document.write( "tan theta = ??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343626 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343626\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.) sin < 0, tan < 0, what quadrant will both be in? <BR>\n" );
document.write( "2.) Find the exact value of tan theta, given that sin theta = -1/6 and theta is in quadrant IV. <BR>\n" );
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document.write( "1.) sin<0 in quadrants III and IV. tan<0 in quadrants II and IV.<BR>\n" );
document.write( "Therefore, sin and tan will be in quadrant IV<BR>\n" );
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document.write( "2.) sinx=-1/6=opposite side/hypotenuse<BR>\n" );
document.write( "by Pythagorean Theorem, adjacent side=&#8730;(6^2-1)=&#8730;(36-1)=&#8730;35<BR>\n" );
document.write( "tanx=opposite side/adjacent side=-1/&#8730;35=-&#8730;35/35\r<BR>\n" );
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