document.write( "Question 514905: If Gina leaves now and drives 66 km/h she will reach Alton just in time for her appointment. On the other hand, if she has lunch first and leaves in 40 minutes, she will have to drive 90km/h to make her appointment. How far away is Alton? \n" ); document.write( "

Algebra.Com's Answer #343613 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+t+\"$ = the time in hours for her to make the
\n" ); document.write( "appointment if she drives at 66 km/hr
\n" ); document.write( "Let $\"d\"$ = the distance to Alton
\n" ); document.write( "given:
\n" ); document.write( " $\"+d+=+66t+\"$
\n" ); document.write( "Going the same distance in in $\"+40%2F60+\"$ hrs less time
\n" ); document.write( " $\"+d+=+90%2A%28+t+-+2%2F3+%29+\"$
\n" ); document.write( "By substitution
\n" ); document.write( " $\"+66t+=+90%2A%28+t+-+2%2F3+%29+\"$
\n" ); document.write( " $\"+66t+=+90t+-+60+\"$
\n" ); document.write( " $\"+24t+=+60+\"$
\n" ); document.write( " $\"+t+=+2.5+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+d+=+66t+\"$
\n" ); document.write( " $\"+d+=+66%2A2.5+\"$
\n" ); document.write( " $\"+d+=+165+\"$
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+d+=+90%2A%28+t+-+2%2F3+%29+\"$
\n" ); document.write( " $\"+d+=+90%2A%28+5%2F2+-+2%2F3+%29+\"$
\n" ); document.write( " $\"+d+=+90%2A%28+15%2F6+-+4%2F6+%29+\"$
\n" ); document.write( " $\"+d+=+90%2A%2811%2F6%29+\"$
\n" ); document.write( " $\"+d+=+15%2A11+\"$
\n" ); document.write( " $\"+d+=+165+\"$
\n" ); document.write( "Alton is 165 km away \n" ); document.write( "

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