document.write( "Question 47341: $\"x%2B4%28x%2B3%29=17\"$ \n" ); document.write( "

Algebra.Com's Answer #34361 by rchill(405) $\"\"$ $\"About$

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First expand the equation thusly $\"x%2B4%2Ax%2B4%2A3=17\"$ . That equates to $\"x%2B4x%2B12=17\"$ . Combining like terms produces $\"5x%2B12=17\"$ . Now subtract 12 from both sides: $\"5x%2B12-12=17-12\"$ , or $\"5x=5\"$ . Dividing both sides by 5 produces $\"5x%2F5=5%2F5\"$ which simplifies to $\"x=1\"$ . \n" ); document.write( "

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