document.write( "Question 51421This question is from textbook introductory algebra
\n" ); document.write( ": 8x - 1 = 23 - 4x\r
\n" ); document.write( "\n" ); document.write( "If I could see the steps in solving this I can figure out the rest of them. Thank you. \r
\n" ); document.write( "\n" ); document.write( "Rick Kalbfell \n" ); document.write( "

Algebra.Com's Answer #34356 by rchill(405) $\"\"$ $\"About$

You can put this solution on YOUR website!
You need to get like terms on the same side of the equation; i.e., get the 'x' terms all on one side and the scalars on the opposite side. So, let's start by adding 1 to both sides of the equation: $\"8x+-+1+%2B+1+=+23+-+4x+%2B+1\"$ . That equates to: $\"8x+=+24+-+4x\"$ . Next, let's add 4x to both sides thusly: $\"8x+%2B+4x+=+24+-+4x+%2B+4x\"$ , which simplifies to: 12x = 24. To solve for x, we have to divide both sides by 12: $\"+12x+%2F+12+=+24%2F12+\"$ , and that simplifies to $\"x=2\"$ . To check our work, we substitute 2 into the original equation. This produces: $\"8%2A2-1=23-4%2A2\"$ , which equates to $\"16-1=23-8\"$ , which simplifies to 15=15. Because 15=15 is a true statement, that proves our answer of $\"x=2\"$ is correct. \n" ); document.write( "

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