document.write( "Question 514761: find an equation of a line that passes through the point (6,-1) and perpendicular to the line 5x + 2y =-9 \n" ); document.write( "

Algebra.Com's Answer #343553 by mananth(16946) $\"\"$ $\"About$

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5 x + 2 y = -9
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "2 y = -5 x -9
\n" ); document.write( "Divide by 2
\n" ); document.write( " y = -2.500 x + -4.5
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = -2.50 =-5/2
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be 2/5
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\n" ); document.write( "m= 2/5 ,point ( 6 , -1 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "-1 = 2.40 + b
\n" ); document.write( "b= -3.4=-17/5
\n" ); document.write( "m= 2/5
\n" ); document.write( "The required equation is y = 2/ 5 x -17/ 5
\n" ); document.write( "m.ananth@hotmail.ca
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