document.write( "Question 514380: PLease help I do not know how to even begin to attempt to solve this.\r
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Algebra.Com's Answer #343392 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Expand the binomial (k-3)^3
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\n" ); document.write( "= 3C0*k^3 + 3C1*k^2(-3)^1 + 3C2k(-3)^2 + 3C3*(-3)^3
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\n" ); document.write( "= k^3 + 3k^2(-3) + 3k(9) + (-27)
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\n" ); document.write( "= k^3 -9k^2 + 27k - 27
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\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.
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