document.write( "Question 514361: Kevin is two years younger than Ed,who is two-thirds plus six years as old as Bob,who is five times as old as a quater of Kevin's age.How old will Bob be in ten years. \n" ); document.write( "

Algebra.Com's Answer #343390 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"k\"$ = Kevin's age now
\n" ); document.write( "Let $\"e\"$ = Ed's age now
\n" ); document.write( "Let $\"b\"$ = Bob's age now
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"+k+=+e+-+2+\"$
\n" ); document.write( "(2) $\"+e+=+%282%2F3%29%2Ab+%2B+6+\"$
\n" ); document.write( "(3) $\"+b+=+5%2A%281%2F4%29%2Ak+\"$
\n" ); document.write( "-----------------
\n" ); document.write( "This is 3 equations and 3 unknowns, so it
\n" ); document.write( "should be solvable
\n" ); document.write( "(1) $\"+e+=+k+%2B+2+\"$
\n" ); document.write( "By substitution:
\n" ); document.write( "(2) $\"+k+%2B+2+=+%282%2F3%29%2Ab+%2B+6+\"$
\n" ); document.write( "(2) $\"+3k+%2B+6+=+2b+%2B+18+\"$
\n" ); document.write( "(2) $\"+2b+=+3k+-+12+\"$
\n" ); document.write( "(2) $\"+b+=+%283%2F2%29%2Ak+-+6+\"$
\n" ); document.write( "By substitution:
\n" ); document.write( "(3) $\"+%283%2F2%29%2Ak+-+6+=+%285%2F4%29%2Ak+\"$
\n" ); document.write( "Multiply both sides by $\"4\"$
\n" ); document.write( "(3) $\"+6k+-+24+=+5k+\"$
\n" ); document.write( "(3) $\"+k+=+24+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+e+=+k+%2B+2+\"$
\n" ); document.write( "(1) $\"+e+=+24+%2B+2+\"$
\n" ); document.write( "(1) $\"+e+=+26+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+b+=+%283%2F2%29%2Ak+-+6+\"$
\n" ); document.write( "(2) $\"+b+=+%283%2F2%29%2A24+-+6+\"$
\n" ); document.write( "(2) $\"+b+=+30+\"$
\n" ); document.write( "Kevin is 24
\n" ); document.write( "Ed is 26
\n" ); document.write( "Bob is 30\r
\n" ); document.write( "\n" ); document.write( "
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