document.write( "Question 514262: The first of three numbers exceeds twice the second number by 4, while the third number is twice the first. If the sum of the three numbers is 54, find the numbers. \n" ); document.write( "

Algebra.Com's Answer #343369 by plover(15) $\"\"$ $\"About$

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Let the three numbers be x , y , z
\n" ); document.write( "From the data we conclude :
\n" ); document.write( "x=2y+4 (1)
\n" ); document.write( "z=2x (2)
\n" ); document.write( "From (1)
\n" ); document.write( "x=2y+4
\n" ); document.write( "x-4=2y
\n" ); document.write( "or , 2y=x-4
\n" ); document.write( "y= $\"%28x-4%29%2F2\"$ (3)\r
\n" ); document.write( "\n" ); document.write( "Adding (3) and (2)
\n" ); document.write( "z+y= $\"2x%2B%28x-4%29%2F2\"$
\n" ); document.write( "z+y= $\"%284x%2Bx-4%29%2F2\"$
\n" ); document.write( "Adding x on both side
\n" ); document.write( "x+y+z= $\"%285x-4%29%2F2%2Bx\"$
\n" ); document.write( "54= $\"%285x-4%2B2x%29%2F2\"$ given sum of the three numbers is 54
\n" ); document.write( "108=7x-4
\n" ); document.write( "108+4=7x
\n" ); document.write( "x= $\"112%2F7\"$
\n" ); document.write( " =16
\n" ); document.write( "From (2)
\n" ); document.write( "z=2(16)
\n" ); document.write( " =32
\n" ); document.write( "y= $\"%2816-4%29%2F2\"$
\n" ); document.write( " = $\"12%2F2\"$
\n" ); document.write( " =6
\n" ); document.write( " \n" ); document.write( "

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