document.write( "Question 51380: Please help me solve the following problem; Write the eqation of the line that passes through the point?(2,1) and is parallel to the line with the eqation y=5/2x + 6. I honestly do not know where to even begin on this. \n" ); document.write( "
Algebra.Com's Answer #34336 by Earlsdon(6294)\"\" \"About 
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Let's write the required equation of the line in the \"slope-intercept\" form: \"y+=+mx%2Bb\" Where: m is the slope of the line and b is the y-intercept of the line.\r
\n" ); document.write( "\n" ); document.write( "Remember that parallel lines have the same slope.
\n" ); document.write( "So, your new line is parallel the the line whose equation is:
\n" ); document.write( "\"y+=+%285%2F2%29x%2B6\" Comparing this with the slope-intercept form:
\n" ); document.write( "\"y+=+mx%2Bb\" you can see that the slope of this line is \"m+=+5%2F2\" and, because the new line is parallel to this, it too will have a slope of \"m+=+5%2F2\".
\n" ); document.write( "So, step 1, for the new line, you can write:
\n" ); document.write( "\"y+=+%285%2F2%29x+%2B+b\" Now all you need to do is to find the value of b, the y-intercept of the new line.
\n" ); document.write( "You can do this by substituting the x- and y-coordinates of the given point (2, 1) into the equation \"y+=+%285%2F2%29x+%2B+b\" and solve for b.\r
\n" ); document.write( "\n" ); document.write( "\"1+=+%285%2F2%29%282%29+%2B+b\" Simplify this.
\n" ); document.write( "\"1+=+5+%2B+b\" Subtract 5 from both sides of the equation.
\n" ); document.write( "\"-4+=+b\" You can write the final equation now that you have the slope \"m+=+5%2F2\" and the y-intercept \"b+=+-4\":\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%285%2F2%29x+-+4\" ...and that's it!
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