document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=514108>Question 514108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 36. The length is 3 less than twice the width. Find the width.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343293 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 2W-3<BR>\n" );
document.write( "P = 2(L+W) = 36<BR>\n" );
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document.write( "2(2W-3 +W) = 36<BR>\n" );
document.write( "4W -6 +2W = 36<BR>\n" );
document.write( "6W = 42<BR>\n" );
document.write( "W = 7<BR>\n" );
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document.write( "L = 2W-3 = 14-3 = 11<BR>\n" );
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document.write( "2(L+W) = 2(11+7) = 2(18) = 36<BR>\n" );
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document.write( "Answer: Width = 7, Length = 11.<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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