document.write( "Question 514085: the width of a rectangle is 12 ft less than the length. the area of the rectangle is 540 square ft. Find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #343282 by mananth(16946)![]() ![]() You can put this solution on YOUR website! length = x \n" ); document.write( "width = (x-12)\r \n" ); document.write( "\n" ); document.write( "Area = L*W\r \n" ); document.write( "\n" ); document.write( "Area = x(x-12)=540\r \n" ); document.write( "\n" ); document.write( "x^2-12x=540 \n" ); document.write( "x^2-12x-540=0 \n" ); document.write( "x^2-30x+18x-540=0 \n" ); document.write( "x(x-30)+18(x-30)=0 \n" ); document.write( "(x-30)(x+18)=0 \n" ); document.write( "x=30 which is positive \r \n" ); document.write( "\n" ); document.write( "length = 30 ft \n" ); document.write( "width = 18 feet\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |