document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=514085>Question 514085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is 12 ft less than the length. the area of the rectangle is 540 square ft. Find the dimensions of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343281 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343281\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = W+12<BR>\n" );
document.write( "A = L*W = 540 sq ft<BR>\n" );
document.write( "A = (W+12)*W = 540<BR>\n" );
document.write( "W^2+12W-540 = 0<BR>\n" );
document.write( "(W +30)(W-18) = 0<BR>\n" );
document.write( "W = -30 or 18<BR>\n" );
document.write( "Negative width is nonsense, so<BR>\n" );
document.write( "W = 18<BR>\n" );
document.write( "L = 18+12 = 30<BR>\n" );
document.write( "Answer: Dimensions are length 30, width 18.<BR>\n" );
document.write( "Done. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );