document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=514016>Question 514016</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 15 cm and one of its legs is 11 cm . What is the measurement of the other leg ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343256 by </B><A HREF=/tutors/aboutme.mpl?userid=10301650><B>10301650(32)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=10301650><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=10301650><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343256\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c^2=a^2+b^2 --> FORMULA<BR>\n" );
document.write( " c (hypotenuse)= 15<BR>\n" );
document.write( " a= 11<BR>\n" );
document.write( " b= ?<BR>\n" );
document.write( " -----: you need to find the b. now, you need to transpose the a to the other side to solve for the other leg of the triangle which is the b.\r<BR>\n" );
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document.write( "c^2-a^2=b^2<BR>\n" );
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document.write( "15^2-11^2=b^2<BR>\n" );
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document.write( "225-121=b^2<BR>\n" );
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document.write( "104=b^2<BR>\n" );
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document.write( "sqrt(104)= sqrt(b^2)<BR>\n" );
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document.write( "10.2= b (ANSWER) </SPAN>\n" );
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