document.write( "Question 511723: please help me with this, find the vertices, foci and length of major and minor axis :
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document.write( "x2+2y2-6x-8y=1
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document.write( "I know how to find the vertices, foci and length of major and minor but I have no idea how to complete the square for the eq, can you please show me. \n" );
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Algebra.Com's Answer #343250 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! find the vertices, foci and length of major and minor axis : \n" ); document.write( "x2+2y2-6x-8y=1 \n" ); document.write( "** \n" ); document.write( "x^2+2y^2-6x-8y=1 \n" ); document.write( "complete the square \n" ); document.write( "(x^2-6x+9)+2(y^2-4y+4)=1+9+8=18 \n" ); document.write( "(x-3)^2+2(y-2)^2=18 \n" ); document.write( "divide by 18 \n" ); document.write( "(x-3)^2/18+(y-2)^2/9=1 \n" ); document.write( "This is an equation of an ellipse with horizontal major axis of the standard form: \n" ); document.write( "(x-h)^2/a^2+(y-k)^2/b^2=1, a>b, (h,k) being the (x,y) coordinates of the center \n" ); document.write( "For given equation: (x-3)^2/18+(y-2)^2/9=1 \n" ); document.write( "center: (3,2) \n" ); document.write( "a^2=18 \n" ); document.write( "a=√18=4.24 \n" ); document.write( "length of major axis=2a=2√18=8.49 \n" ); document.write( "vertices=(3±a,2)=(3±√18,2)=(3+√18,2) and (3-√18,2) \n" ); document.write( ".. \n" ); document.write( "b^2=9 \n" ); document.write( "b=√9=3 \n" ); document.write( "length of minor axis=2b=6 \n" ); document.write( ".. \n" ); document.write( "Foci \n" ); document.write( "c^2=a^2-b^2=18-9=9 \n" ); document.write( "c=√9=3 \n" ); document.write( "Foci=(3±c,2)=(3±3,2)=(6,2) and (0,2) \n" ); document.write( " |