document.write( "Question 511723: please help me with this, find the vertices, foci and length of major and minor axis :
\n" ); document.write( "x2+2y2-6x-8y=1
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\n" ); document.write( "I know how to find the vertices, foci and length of major and minor but I have no idea how to complete the square for the eq, can you please show me.
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Algebra.Com's Answer #343250 by lwsshak3(11628)\"\" \"About 
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find the vertices, foci and length of major and minor axis :
\n" ); document.write( "x2+2y2-6x-8y=1
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\n" ); document.write( "x^2+2y^2-6x-8y=1
\n" ); document.write( "complete the square
\n" ); document.write( "(x^2-6x+9)+2(y^2-4y+4)=1+9+8=18
\n" ); document.write( "(x-3)^2+2(y-2)^2=18
\n" ); document.write( "divide by 18
\n" ); document.write( "(x-3)^2/18+(y-2)^2/9=1
\n" ); document.write( "This is an equation of an ellipse with horizontal major axis of the standard form:
\n" ); document.write( "(x-h)^2/a^2+(y-k)^2/b^2=1, a>b, (h,k) being the (x,y) coordinates of the center
\n" ); document.write( "For given equation: (x-3)^2/18+(y-2)^2/9=1
\n" ); document.write( "center: (3,2)
\n" ); document.write( "a^2=18
\n" ); document.write( "a=√18=4.24
\n" ); document.write( "length of major axis=2a=2√18=8.49
\n" ); document.write( "vertices=(3±a,2)=(3±√18,2)=(3+√18,2) and (3-√18,2)
\n" ); document.write( "..
\n" ); document.write( "b^2=9
\n" ); document.write( "b=√9=3
\n" ); document.write( "length of minor axis=2b=6
\n" ); document.write( "..
\n" ); document.write( "Foci
\n" ); document.write( "c^2=a^2-b^2=18-9=9
\n" ); document.write( "c=√9=3
\n" ); document.write( "Foci=(3±c,2)=(3±3,2)=(6,2) and (0,2)
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