document.write( "Question 513998: THe perimeter of a rectangle is 310 ft. THe length is 5 ft greater than the width. What is the length \n" ); document.write( "
Algebra.Com's Answer #343237 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the length. Then if the length is 5 feet greater than the width, the width must be 5 feet smaller than the length, so the width is . The perimeter is two times the length plus two times the width.\r
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\n" ); document.write( "\n" ); document.write( "Solve for \r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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