document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513949>Question 513949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Twice a number decreased by 39 is five times the sum of the number and two times the number . </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343227 by </B><A HREF=/tutors/aboutme.mpl?userid=drcole><B>drcole(72)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drcole><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343227\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We need to write this problem out algebraically.  Let x be the number.  Then twice that number is 2x, and twice the number decreased by 39 can be written as:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2x+-+39+ ALIGN=MIDDLE  ALT=\"+2x+-+39+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The sum of the number and two times the number would be \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+2x ALIGN=MIDDLE  ALT=\"x+%2B+2x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The problem states that twice a number decreased by 39 equals five time the sum of the number and two times the number.  We can therefore write this equation algebraically as:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2x+-+39+=+5%28x+%2B+2x%29+ ALIGN=MIDDLE  ALT=\"+2x+-+39+=+5%28x+%2B+2x%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now we simplify our equation and solve for x:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2x+-+39+=+5%283x%29+ ALIGN=MIDDLE  ALT=\"+2x+-+39+=+5%283x%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (combine like terms)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2x+-+39+=+15x+ ALIGN=MIDDLE  ALT=\"+2x+-+39+=+15x+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (simplify the right hand side by multiplying)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+-39+=+13x+ ALIGN=MIDDLE  ALT=\"+-39+=+13x+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (subtract 2x from both sides)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+-3+=+x+ ALIGN=MIDDLE  ALT=\"+-3+=+x+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (divide both sides by 13)\r<BR>\n" );
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document.write( "So x = -3.  Let's check this: twice of -3 is -6, so twice of 3 decreased by 39 equals -6 - 39 = -45.  The sum of -3 and twice of -3 is -3 + (-6) = -9, and five times that is -45.  So the two sides match, and x = -3 is our solution. </SPAN>\n" );
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