document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513943>Question 513943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If angle A and angle B are supplementary find the value of x<BR>\n" );
document.write( "Measure of angle A= 2x, m of angle B= x-15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343223 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If angle A and angle B are supplementary, then A = 180-B, so...<BR>\n" );
document.write( "2x = 180-(x-15) Simplify.<BR>\n" );
document.write( "2x = 180-x+15 Add x.<BR>\n" );
document.write( "3x = 180+15 <BR>\n" );
document.write( "3x = 195 Divide by 3.<BR>\n" );
document.write( "x = 65\r<BR>\n" );
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