document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513841>Question 513841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a triangle ABC, angle B is four times angle A and angle C is 2 degrees less than 5 times angle A. Find the size of the angles. what is the size of angle A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343164 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in a triangle ABC, angle B is four times angle A and angle C is 2 degrees less than 5 times angle A. Find the size of the angles. what is the size of angle A?<BR>\n" );
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document.write( "A + B + C = 180<BR>\n" );
document.write( "B = 4A<BR>\n" );
document.write( "C = 5A-2<BR>\n" );
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document.write( "Substitute for B and C and solve for \"A\":<BR>\n" );
document.write( "A + 4A + 5A-2 = 180<BR>\n" );
document.write( "10A = 182<BR>\n" );
document.write( "A = 18.2 degrees<BR>\n" );
document.write( "B = 72.8 degrees<BR>\n" );
document.write( "C = 89 degrees<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );