document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513815>Question 513815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i am working on negative exponents and i dont know how to solve -3 to the exponent of 9 dived by -3 to the power of 9 im stuck can you please help me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343157 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i am working on negative exponents and i dont know how to solve -3 to the exponent of 9 divided by -3 to the power of 9 im stuck can you please help me?<BR>\n" );
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document.write( "This problem does not have a negative exponent:<BR>\n" );
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document.write( "(-3)^9/(-3)^9 = 1<BR>\n" );
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document.write( "(-3)^9/-3^9 = [(-1)^9*(3^9)]/[-(3^9)] = [-(3^9)/-(3^9)] = 1<BR>\n" );
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document.write( "-3^9/-3^9 = 1<BR>\n" );
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document.write( "Note: A negative in the exponent means you should <BR>\n" );
document.write( "invert the base.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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