document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=513776>Question 513776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Students are traveling in two cars to a football game 150 miles away. The first car leaves on time and travels at an average speed of 48mph. The second starts 1/2 hours late and travels at an average speed of 58 mph. At these speeds, how long will it take the second car to catch up to the first? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #343154 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=343154\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Students are traveling in two cars to a football game 150 miles away. The first car leaves on time and travels at an average speed of 48mph. The second starts 1/2 hours late and travels at an average speed of 58 mph. At these speeds, how long will it take the second car to catch up to the first?<BR>\n" );
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document.write( "The 1st car has a head start of 48 mph * 0.5 h = 24 mi<BR>\n" );
document.write( "The relative speed of the two cars = 58 - 48 = 10 mph<BR>\n" );
document.write( "At this relative speed, the 24 mile separation is made up in 24 mi/10 mph = 2.4 hr<BR>\n" );
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